Identify the vertex and the axis of symmetry of the graph functio

y=3(x+2)^2-3

Could someone please help me

2 answers

as you should know, the parabola

y = a(x-h)^2 + k

has vertex at (h,k) and axis x=h.

So, just read them off from your equation. Just be sure to make it fir the format exactly. Your equation is

y = 2(x-(-2)) + (-3), so h = -2 and k = -3

vertex: (-2,-3)
axis: x = -2
Oh thank you for explaining