The given equation is 16x^2 + 4y^2 = 16, which can be simplified by dividing both sides by 16 to get x^2/1 + y^2/4 = 1. This is the equation of an ellipse centered at the origin with semi-major axis of length √4 = 2 and semi-minor axis of length √1 = 1.
Therefore, the type of conic section that has the given equation is an ellipse.
The domain of the ellipse is all real values of x that satisfy the equation, which is given by -2 ≤ x ≤ 2. The range of the ellipse is all real values of y that satisfy the equation, which is given by -1 ≤ y ≤ 1.
identify the type of conic section that has the equation 16x^2+4y^2=16 and identify its domain and range
1 answer
1 answer