To find the slope and y-intercept of the equation \(4x - 3y = 12\), we can start by rewriting it in slope-intercept form, which is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.
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Start with the original equation: \[ 4x - 3y = 12 \]
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Solve for \(y\): \[ -3y = -4x + 12 \]
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Divide everything by \(-3\): \[ y = \frac{4}{3}x - 4 \]
Now, the equation is in the slope-intercept form \(y = mx + b\).
From this equation, we can identify:
- The slope \(m = \frac{4}{3}\)
- The y-intercept \(b = -4\) (which corresponds to the point \((0, -4)\))
Thus, the slope is \(\frac{4}{3}\), and the y-intercept is \((0, -4)\).