To determine whether a function is odd, we need to check if \( f(-x) = -f(x) \) for all \( x \). Let's evaluate each function:
-
\( f(x) = 2x^3 \)
- \( f(-x) = 2(-x)^3 = 2(-x^3) = -2x^3 = -f(x) \)
- This function is odd.
-
\( f(x) = 2(x + 1)^3 \)
- \( f(-x) = 2(-x + 1)^3 = 2(1 - x)^3 \)
- Now, \( (1 - x)^3 = 1 - 3x + 3x^2 - x^3 \)
- Thus, \( f(-x) = 2(1 - 3x + 3x^2 - x^3) = 2 - 6x + 6x^2 - 2x^3 \)
- Since \( f(x) = 2(x + 1)^3 = 2(x^3 + 3x^2 + 3x + 1) = 2x^3 + 6x^2 + 6x + 2 \), \( f(-x) \neq -f(x) \).
- This function is not odd.
-
\( f(x) = 3x^2 \)
- \( f(-x) = 3(-x)^2 = 3x^2 = f(x) \)
- This function is even.
-
\( f(x) = x^4 \)
- \( f(-x) = (-x)^4 = x^4 = f(x) \)
- This function is also even.
Conclusively, the only odd function in the list is:
1. \( f(x) = 2x^3 \)
The function that is not odd is 2. \( f(x) = 2(x + 1)^3 \).