Identify the multiplicities of the linear factors of h(x)=(x+4)(x−1)2(x+3)5 .(1 point)ResponsesThe multiplicity of (x+4) is −4, the multiplicity of (x−1) is 1, and the multiplicity of (x+3) is −3.The multiplicity of left parenthesis x plus 4 right parenthesis is negative 4 , the multiplicity of left parenthesis x minus 1 right parenthesis is 1, and the multiplicity of left parenthesis x plus 3 right parenthesis is negative 3 .The multiplicity of (x+4) is 1, the multiplicity of (x−1) is 2, and the multiplicity of (x+3) is 5.The multiplicity of left parenthesis x plus 4 right parenthesis is 1, the multiplicity of left parenthesis x minus 1 right parenthesis is 2, and the multiplicity of left parenthesis x plus 3 right parenthesis is 5.The multiplicity of (x+4) is 0, the multiplicity of (x−1) is 2, and the multiplicity of (x+3) is 5.The multiplicity of left parenthesis x plus 4 right parenthesis is 0, the multiplicity of left parenthesis x minus 1 right parenthesis is 2, and the multiplicity of left parenthesis x plus 3 right parenthesis is 5.The multiplicity of (x+4) is 4, the multiplicity of (x−1) is −1, and the multiplicity of (x+3) is 3.The multiplicity of left parenthesis x plus 4 right parenthesis is 4, the multiplicity of left parenthesis x minus 1 right parenthesis is negative 1 , and the multiplicity of left parenthesis x plus 3 right parenthesis is 3.

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To identify the multiplicities of the linear factors of the polynomial \( h(x)=(x+4)(x−1)^2(x+3)^5 \), we look at the powers of each factor.

The factor \( (x+4) \) has an exponent of 1, so its multiplicity is 1.

The factor \( (x−1)^2 \) has an exponent of 2, so its multiplicity is 2.

The factor \( (x+3)^5 \) has an exponent of 5, so its multiplicity is 5.

Thus, the multiplicities are:

The multiplicity of \( (x+4) \) is 1.

The multiplicity of \( (x−1) \) is 2.

The multiplicity of \( (x+3) \) is 5.

The correct response is: The multiplicity of \( (x+4) \) is 1, the multiplicity of \( (x−1) \) is 2, and the multiplicity of \( (x+3) \) is 5.

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Identify the multiplicities of the linear factors of h(x)=(x+4)(x−1)2(x+3)5 .(1 point)ResponsesThe multiplicity of (x+4) is −4, the multiplicity of (x−1) is 1, and the multiplicity of (x+3) is −3.The multiplicity of left parenthesis x plus 4 right parenthesis is negative 4 , the multiplicity of left parenthesis x minus 1 right parenthesis is 1, and the multiplicity of left parenthesis x plus 3 right parenthesis is negative 3 .The multiplicity of (x+4) is 1, the multiplicity of (x−1) is 2, and the multiplicity of (x+3) is 5.The multiplicity of left parenthesis x plus 4 right parenthesis is 1, the multiplicity of left parenthesis x minus 1 right parenthesis is 2, and the multiplicity of left parenthesis x plus 3 right parenthesis is 5.The multiplicity of (x+4) is 0, the multiplicity of (x−1) is 2, and the multiplicity of (x+3) is 5.The multiplicity of left parenthesis x plus 4 right parenthesis is 0, the multiplicity of left parenthesis x minus 1 right parenthesis is 2, and the multiplicity of left parenthesis x plus 3 right parenthesis is 5.The multiplicity of (x+4) is 4, the multiplicity of (x−1) is −1, and the multiplicity of (x+3) is 3.The multiplicity of left parenthesis x plus 4 right parenthesis is 4, the multiplicity of left parenthesis x minus 1 right parenthesis is negative 1 , and the multiplicity of left parenthesis x plus 3 right parenthesis is 3.

1 answer

To identify the multiplicities of the linear factors of the polynomial \( h(x)=(x+4)(x−1)^2(x+3)^5 \), we look at the powers of each factor.

The factor \( (x+4) \) has an exponent of 1, so its multiplicity is 1.
The factor \( (x−1)^2 \) has an exponent of 2, so its multiplicity is 2.
The factor \( (x+3)^5 \) has an exponent of 5, so its multiplicity is 5.

Thus, the multiplicities are:

The multiplicity of \( (x+4) \) is 1.
The multiplicity of \( (x−1) \) is 2.
The multiplicity of \( (x+3) \) is 5.

The correct response is: The multiplicity of \( (x+4) \) is 1, the multiplicity of \( (x−1) \) is 2, and the multiplicity of \( (x+3) \) is 5.

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GPT-4o mini · Answer

To identify the multiplicities of the linear factors of the polynomial \( h(x)=(x+4)(x−1)^2(x+3)^5 \), we look at the powers of each factor.

The factor \( (x+4) \) has an exponent of 1, so its multiplicity is 1.
The factor \( (x−1)^2 \) has an exponent of 2, so its multiplicity is 2.
The factor \( (x+3)^5 \) has an exponent of 5, so its multiplicity is 5.

Thus, the multiplicities are:

The multiplicity of \( (x+4) \) is 1.
The multiplicity of \( (x−1) \) is 2.
The multiplicity of \( (x+3) \) is 5.

The correct response is: The multiplicity of \( (x+4) \) is 1, the multiplicity of \( (x−1) \) is 2, and the multiplicity of \( (x+3) \) is 5.