Identify the limiting reactant and determine the mass of the excess reactant remaining when 7.00 g of chlorine gas reacts with 5.00 g of potassium to form potassium chloride.

Answer 1

2molK + 1molClgas create 2molKCl
nK/nClgas=2/1
5/39:7/31=1.3
so Cl gas excess
mClgas(excess) = 7-(5*71/78) = 2.45g