To identify the key parts of a parabola, I would need the equation of the parabola in standard form, vertex form, or factored form. Since you have not provided this equation, I will outline the steps to find each component:
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Vertex: The vertex can be found from the equation of the parabola. If the equation is in the form \(y = ax^2 + bx + c\), the vertex can be found using the formula \(x = -\frac{b}{2a}\).
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Zeros (or x-intercepts): To find the zeros of the parabola, you need to solve the equation \(ax^2 + bx + c = 0\). You can use factoring, completing the square, or the quadratic formula.
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Line of Symmetry: The line of symmetry for a parabola can be expressed as \(x = -\frac{b}{2a}\), which is the x-coordinate of the vertex.
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Y-intercept: The y-intercept is found by evaluating the function at \(x = 0\). This gives you the value \(c\) in the equation \(y = ax^2 + bx + c\). The y-intercept is the ordered pair \((0, c)\).
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Table of values: To complete the table, you need to evaluate the function \(f(x)\) for each \(x\) value (-1, 0, 1, 3, 5). You plug these values into the equation of the parabola.
Please provide the equation of the parabola so I can help you with the specific values.