Identify the first quartile in the following dataset:
5, 7, 9, 4, 3, 2, 1, 0, 11, 12, 6, 3, 4, 3, 2, 6(1 point)
Responses
6.5
6.5
4
4
0
0
2.5
2.5
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11 answers
The first quartile in the dataset is 2.5.
dentify the third quartile in the following dataset:
53.3, 46.9, 48.1, 49.7, 52.1, 47.5, 47.2, 45.5(1 point)
Responses
47.8
47.8
50.9
50.9
53.3
53.3
47.05
47.05
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53.3, 46.9, 48.1, 49.7, 52.1, 47.5, 47.2, 45.5(1 point)
Responses
47.8
47.8
50.9
50.9
53.3
53.3
47.05
47.05
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The third quartile in the dataset is 50.9.
Find the range of the given data set.
51, 13, 98, 42, 76, 28
(1 point)
Responses
23
23
98
51, 13, 98, 42, 76, 28
(1 point)
Responses
23
23
98
To find the range of a dataset, you need to subtract the minimum value from the maximum value.
In the given dataset: 51, 13, 98, 42, 76, 28
The minimum value is 13 and the maximum value is 98.
So, the range is: 98 - 13 = 85
Therefore, the range of the given dataset is 85.
In the given dataset: 51, 13, 98, 42, 76, 28
The minimum value is 13 and the maximum value is 98.
So, the range is: 98 - 13 = 85
Therefore, the range of the given dataset is 85.
Find the interquartile range of the given dataset.
11, 13, 22, 17, 14, 21, 27, 15
(1 point)
Responses
13.5
13.5
21.5
21.5
6.5
6.5
8
8
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11, 13, 22, 17, 14, 21, 27, 15
(1 point)
Responses
13.5
13.5
21.5
21.5
6.5
6.5
8
8
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To find the interquartile range (IQR) of a dataset, you need to find the difference between the first quartile (Q1) and the third quartile (Q3).
Given dataset: 11, 13, 22, 17, 14, 21, 27, 15
First you need to find the Q1 and Q3:
- Q1: The median of the lower half of the data set = (13 + 14) / 2 = 13.5
- Q3: The median of the upper half of the data set = (21 + 22) / 2 = 21.5
Now, calculate the IQR:
IQR = Q3 - Q1
IQR = 21.5 - 13.5
IQR = 8
Therefore, the interquartile range of the given dataset is 8.
Given dataset: 11, 13, 22, 17, 14, 21, 27, 15
First you need to find the Q1 and Q3:
- Q1: The median of the lower half of the data set = (13 + 14) / 2 = 13.5
- Q3: The median of the upper half of the data set = (21 + 22) / 2 = 21.5
Now, calculate the IQR:
IQR = Q3 - Q1
IQR = 21.5 - 13.5
IQR = 8
Therefore, the interquartile range of the given dataset is 8.
The heights in inches of six basketball players at a local high school are given as a dataset.
70, 78, 74, 82, 68, 75
Find the range and the interquartile range of the dataset.
(1 point)
Responses
The range is 5, and the interquartile range is 8.
The range is 5, and the interquartile range is 8.
The range is
70, 78, 74, 82, 68, 75
Find the range and the interquartile range of the dataset.
(1 point)
Responses
The range is 5, and the interquartile range is 8.
The range is 5, and the interquartile range is 8.
The range is
To find the range and interquartile range for the given dataset: 70, 78, 74, 82, 68, 75.
First, let's find the range:
Range = Maximum value - Minimum value
Maximum value = 82
Minimum value = 68
Range = 82 - 68 = 14
Now, let's find the interquartile range (IQR):
First, order the data in ascending order: 68, 70, 74, 75, 78, 82
Q1 (First Quartile): (70 + 74) / 2 = 72
Q3 (Third Quartile): (75 + 78) / 2 = 76.5
IQR = Q3 - Q1
IQR = 76.5 - 72
IQR = 4.5
So, the range of the dataset is 14, and the interquartile range is 4.5.
First, let's find the range:
Range = Maximum value - Minimum value
Maximum value = 82
Minimum value = 68
Range = 82 - 68 = 14
Now, let's find the interquartile range (IQR):
First, order the data in ascending order: 68, 70, 74, 75, 78, 82
Q1 (First Quartile): (70 + 74) / 2 = 72
Q3 (Third Quartile): (75 + 78) / 2 = 76.5
IQR = Q3 - Q1
IQR = 76.5 - 72
IQR = 4.5
So, the range of the dataset is 14, and the interquartile range is 4.5.
onsider the following dataset: 22, 29, 31, 30, 22, 24, 18, 20, 25. What is the third quartile’s value? Round to the nearest tenth if necessary.(1 point)
To find the Third Quartile (Q3) of the dataset: 22, 29, 31, 30, 22, 24, 18, 20, 25, follow these steps:
1. Order the data in ascending order: 18, 20, 22, 22, 24, 25, 29, 30, 31.
2. Q3 is the median of the upper half of the dataset.
3. Since the dataset has an odd number of values, Q3 will be the median of the values to the right of the overall median.
4. The overall median is the middle value, which is 24.
5. The values to the right of the overall median are: 25, 29, 30, 31.
6. The median of these values is (29 + 30) / 2 = 29.5
Therefore, the third quartile's value (Q3) in the dataset is 29.5.
1. Order the data in ascending order: 18, 20, 22, 22, 24, 25, 29, 30, 31.
2. Q3 is the median of the upper half of the dataset.
3. Since the dataset has an odd number of values, Q3 will be the median of the values to the right of the overall median.
4. The overall median is the middle value, which is 24.
5. The values to the right of the overall median are: 25, 29, 30, 31.
6. The median of these values is (29 + 30) / 2 = 29.5
Therefore, the third quartile's value (Q3) in the dataset is 29.5.
3 answers