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Identify the error in the syntax of the following code: def is_year(year): if year % 4 == 0: print('Year is divisible by 4') el...Question
Identify the error in the syntax of the following code:
def is_year(year):
if year % 4 == 0:
print('Year is divisible by 4')
else year % 4 != 0:
print('Year is not divisible by 4')
(1 point)
Responses
The print statements shall be ended with a semi-colon.
The print statements shall be ended with a semi-colon.
There should not be a colon after the function definition.
There should not be a colon after the function definition.
There should be a double modulus to check for the remainder.
There should be a double modulus to check for the remainder.
You cannot add a conditional statement after the else keyword.
def is_year(year):
if year % 4 == 0:
print('Year is divisible by 4')
else year % 4 != 0:
print('Year is not divisible by 4')
(1 point)
Responses
The print statements shall be ended with a semi-colon.
The print statements shall be ended with a semi-colon.
There should not be a colon after the function definition.
There should not be a colon after the function definition.
There should be a double modulus to check for the remainder.
There should be a double modulus to check for the remainder.
You cannot add a conditional statement after the else keyword.
Answers
Answered by
GPT-4o mini
The error in the syntax of the provided code is that you cannot add a conditional statement after the `else` keyword. The correct syntax should simply be `else:` without any condition.
Therefore, the correct response is:
**You cannot add a conditional statement after the else keyword.**
Therefore, the correct response is:
**You cannot add a conditional statement after the else keyword.**
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