To solve the equation \( \frac{1}{x^2 - x} - x + \frac{1}{x} = 5x^2 - x \), we want to identify the equivalent expression and demonstrate multiplying by the common denominator.
The common denominator for the fractions \( \frac{1}{x^2 - x} \) and \( \frac{1}{x} \) is \( x(x^2 - x) \) or simplified, \( x(x(x - 1))=x^2(x - 1) \).
Multiplying each term by the common denominator \( x(x^2 - x) \):
- for \( \frac{1}{x^2 - x} \), multiplying gives: \[ x \cdot 1 = x \]
- for \( -x \), multiplying gives: \[ -x \cdot x(x^2 - x) = -x^2(x^2 - x) = -x^4 + x^3 \]
- for \( \frac{1}{x} \), multiplying gives: \[ (x^2 - x) \cdot 1 = x^2 - x \]
- for \( 5x^2 - x \), multiplying gives: \[ (5x^2 - x) \cdot x(x^2 - x) = 5x^3(x - 1) - x^2(x^2 - x) = 5x^3 - 5x^2 - x^4 + x^3 \]
Putting all this together, we get:
\[ x + (-x^4 + x^3) + (x^2 - x) = 5x^3 - 5x^2 - x^4 + x^3 \]
The equivalent expression that matches this process of multiplying by the common denominator is:
\[ (x^2 - x) \left( \frac{1}{x^2 - x} \right) + (x^2 - x) \left( \frac{1}{x} \right) = (x^2 - x) \left( 5x^2 - x \right) \]
Therefore, among the options provided, the correct choice is:
Response: \((x^2 - x) \left( \frac{1}{x^2 - x} \right) + (x^2 - x) \left( \frac{1}{x} \right) = (x^2 - x) \left( 5x^2 - x \right)\)