y-1= 3x-(-2)
y = 3x + 3
identify the equation of the line through (-2, 1) and parallel to y = 3x + 1
2 answers
Since the new equation has the same slope it must look like
y = 3x+ b
sub in the point (-2,1)
1 = 3(-2) + b
b = 7
new equation: y = 3x + 7
y = 3x+ b
sub in the point (-2,1)
1 = 3(-2) + b
b = 7
new equation: y = 3x + 7