To analyze the given equation of the parabola \( f(x) = 3(x + 2)^2 - 1 \), we will identify its characteristics:
1. Vertex
The general form of a parabola in vertex form is \( f(x) = a(x - h)^2 + k \), where \((h, k)\) is the vertex.
In this case:
- \( a = 3 \)
- \( h = -2 \) (note the sign change)
- \( k = -1 \)
Vertex: \((-2, -1)\)
2. Maximum or Minimum Point
Since \( a = 3 \) (which is positive), the parabola opens upwards. Therefore, the vertex represents a minimum point.
Minimum Point: Yes, the vertex is a minimum point.
3. Axis of Symmetry
The axis of symmetry can be found using the \( x \)-coordinate of the vertex. The equation of the axis of symmetry is \( x = h \).
Axis of Symmetry: \( x = -2 \)
4. Domain
The domain of a parabola is all real numbers unless otherwise restricted.
Domain: \( (-\infty, \infty) \)
5. Range
Since the parabola opens upwards and has its minimum point at the vertex \( (-2, -1) \), the \( y \)-values start from \(-1\) and go to \(\infty\).
Range: \( [-1, \infty) \)
Summary
- Vertex: \((-2, -1)\)
- Minimum Point: Yes
- Axis of Symmetry: \( x = -2 \)
- Domain: \( (-\infty, \infty) \)
- Range: \( [-1, \infty) \)