http://home.alltel.net/okrebs/page64.html
see problem six.
Identify th equation of the parabola whose focus is at (5,-1) and whose directrix is x=3
I don't see any examples of this kind of problem.
is this right?
(x-5)^2+(y+1)^2=(x-3)^2
so
-10x+25+y^2+2y+1=-6x+9
4x=y^2+2y+17
3 answers
vertex=(-5,-1)
p=-6
4p=-24
(x-5)=(-24)(y+1)^2
p=-6
4p=-24
(x-5)=(-24)(y+1)^2
correction (y+3)^2