Identify th equation of the parabola whose focus is at (5,-1) and whose directrix is x=3

I don't see any examples of this kind of problem.

is this right?

(x-5)^2+(y+1)^2=(x-3)^2
so
-10x+25+y^2+2y+1=-6x+9
4x=y^2+2y+17

3 answers

http://home.alltel.net/okrebs/page64.html

see problem six.
vertex=(-5,-1)
p=-6
4p=-24
(x-5)=(-24)(y+1)^2
correction (y+3)^2
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