fusion of ice.
First, let's consider the energy transfers when the first 50g of ice are added.
The energy gained by the ice when it melts is given by: Q1 = m1 * L, where m1 is the mass of the ice (50g) and L is the specific latent heat of fusion (which we are trying to find).
The energy lost by the 200g of water when the temperature drops from 70°C to 40°C is given by: Q2 = m2 * c * ΔT2, where m2 is the mass of the water (200g), c is the specific heat capacity of water (4.18 J/g°C), and ΔT2 is the change in temperature (70 - 40 = 30°C).
Since the system is thermally isolated, the energy gained by the ice should be equal to the energy lost by the water. Thus, Q1 = Q2.
50 * L = 200 * 4.18 * 30
L = (200 * 4.18 * 30) / 50
L = 502.8 J/g
Now, let's consider the energy transfers when an additional 80g of ice is added.
The energy gained by the ice when it melts is given by: Q3 = m3 * L, where m3 is the mass of the ice (80g) and L is the specific latent heat of fusion (which we found earlier to be 502.8 J/g).
The energy lost by the 250g of water and melted ice when the temperature drops from 40°C to 10°C is given by: Q4 = m4 * c * ΔT4, where m4 is the mass of the water (200g + 50g = 250g), c is the specific heat capacity of water (4.18 J/g°C), and ΔT4 is the change in temperature (40 - 10 = 30°C).
Again, since the system is thermally isolated, the energy gained by the ice should be equal to the energy lost by the water. Thus, Q3 = Q4.
80 * L = 250 * 4.18 * 30
L = (250 * 4.18 * 30) / 80
L = 393.6 J/g
Since we got different values for the specific latent heat of fusion in each case, we can take the average to get a more accurate value.
L = (502.8 + 393.6) / 2
L = 448.2 J/g
The specific latent heat of fusion of ice is approximately 448.2 J/g.
Ice at 0 degree celcuis is added to 200g of water initially at 70 degree celcuis in a vacuum flask.When 50g of ice has been added and has all melted the temperature of the flask and contents is 40 degree Celsius when a further 80gm of ice has been added and has all melted the temperature of the whole is 10 degree Celsius calculate the specific latent heat of the
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