I would really appreciate if someone could help me out.
A test for a certain drug produces a false negative 5% of the time and false positive 8% of the time. Suppose 12% of the employees at a certain company use the drug.
If an employee at the company tests positive, what is the probability that he or she does not use the drug?
2 answers
(1-.12) * .08 = ?
PsyDAG,
The 1 is equivalent to 100 right since it is 12 out of 100? I had 0.88*0.12.
I was totally wrong.
The 1 is equivalent to 100 right since it is 12 out of 100? I had 0.88*0.12.
I was totally wrong.
1 answer