x^2-16x= y-63
x^2 - 16x + 64 = y+64-63
(x-8)^2 = y+1
symmetric about the vertical axis x = 8
when x = 8, y = -1
I would like to have some help on this problem please. I'm so post to find the vertex and axis of the parabola.Does anyone have an idea?
Y=x²-16x+63.
A)vertex(8,-1)axis=x=8
B)vertex(8,1)axis=x=8
C)vertex(-8,-1)axis=x=-8
D)vertex(-8,1)axis=x=-8
1 answer