This is the same problem as a ball rolls down a board making an angle θ with the horizontal in t=2 seconds over a distance S of 1.3 m.
We ignore the size of the ball, which can slow down the ball.
Let g=acceleration due to gravity = 9.8 m/s²
then
a=acceleration down the board
=g sin(θ)
vi=initial velocity=0
and total time to travel S=1.3 m t,
then
S=vi*t + (1/2)g sin(θ)t²
Solve for θ.
I would be very appreciative if someone could provide me with the formula I would use to plug these figures into a graph.
3. A 2m length of board rests with one end on the floor and the other end on a small stack of bricks. A baseball is rolled up the board and back down again in a total of 4 seconds. The farthest the baseball reached on the board was 130cm.
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