50ml of D50% ( 50gm in 100ml ) consists of 25gm Dextrose
1000ml of N0.45%+D2.5% (2.5 gm in 100 ml) consists 25gm of Dextrose
Thus, total of 50 gm Dextrose in 1050ml of sol. (don't bother about Ns)
: 1050ml=50gm
100ml= 50/1050*100
= 4.76%
I was so thankful to see this exact question answered in a different way but I still don't understand how I'm suppose to know how or what to do on the following question. I just seem to always forget something.
Fifty milliliters of a solution of 50% dextrose is added to a liter of 0.45% NaCl with 2.5% dextrose to yield a solution with a final dextrose concentration of what percent?
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1 answer