i was just wondering if the limit of a funtion exists as it approches a value if both the right side limit and the left side limit both equal the same infinity ( postive inififnty for both sides, or negative infinty for both sides).

i know that if one side is negative infinity and the other side is postive infinity the limit does not exist. But since in this situation both infinties are parrallel, i don't know the answer.

Thank you for your help!

2 answers

Does infinity exist? No. Therefore the limit does not exist.

I am wondering what you mean by both infinities are parallel, I assume you did not mean that.
by that i meant that the inifnity for both sides of the x value,are both postive or oth nergative.
so the answer is no because for exaple even if the left side limit and the right side limit are both postive infinty, since we don't know the value for infinity the limit does not exist.

is that right?
Similar Questions
  1. limit of (x*(y-1)^2*cosx)/(x^2+2(y-1)^2) as (x,y)->(0,1).By evaluating along different paths this limit often goes to 0. This
    1. answers icon 0 answers
    1. answers icon 2 answers
  2. (a) Find the number c such that the limit below exists.Limit as x goes to -2 of: x^2+cx=c-3/x^2+2x (b) Calculate the limit for
    1. answers icon 0 answers
  3. (a) Find the number c such that the limit below exists.Limit as x goes to -2 of: x^2+cx=c-3/x^2+2x (b) Calculate the limit for
    1. answers icon 1 answer
more similar questions