Asked by Juliette

I tried the square root of (note the "nook" of the square root sign has a five in it), of -32 f^6 g^5 h^2. I got -6+2f^5fg times the square root of (with five in the nook) h^2. Is this correct? I have a feelign I messed up on the -6 + 2 part, but I wanted to make sure. If I did not do this correctly, could you offer me an explanation of how to correctly do this? Thanks for your clarifications.

Answers

Answered by Reiny
no, it should have been

-2fg(fifthroot(fg^2))

note fifthroot(-32) = -2, since (-2)^5 = -32
Answered by Michelle
{x|X is a natural number less than 1}
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