I tried the square root of (note the "nook" of the square root sign has a five in it), of -32 f^6 g^5 h^2. I got -6+2f^5fg times the square root of (with five in the nook) h^2. Is this correct? I have a feelign I messed up on the -6 + 2 part, but I wanted to make sure. If I did not do this correctly, could you offer me an explanation of how to correctly do this? Thanks for your clarifications.

Question

I tried the square root of (note the "nook" of the square root sign has a five in it), of -32 f^6 g^5 h^2.   I got -6+2f^5fg times the square root of (with five in the nook) h^2.  Is this correct? I have a feelign I messed up on the -6 + 2 part, but I wanted to make sure.  If I did not do this correctly, could you offer me an explanation of how to correctly do this? Thanks for your clarifications.

Reiny · Answer

no, it should have been -2fg(fifthroot(fg^2)) note fifthroot(-32) = -2, since (-2)^5 = -32

Michelle · Answer

{x|X is a natural number less than 1}