i thought i had the answer right, but i didnt! wat are the first few steps?? an elevator (mass 4850kg) is to be designed so that the maximum acceleration is .0680g. what are the maximum and minimum forces the motor should exert on the supporting cable? i know the answers but don't know how to come up with the work! (max=5.08*10^4N and min=4.43*10^4N)
Goodness. Did you read my response?
Tension= m(g +- a)
Consider the max...
Tension= 4850*( 1.068*9.80665)= you do it.
I am not certain of what you have been instructed to use for g.
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