Asked by Tammy
I think that the goal is to get rid of the 5th root in this case. I know that I have to make whatever is under or in the root -in this case the number is X equal some number to the fifth power.
I am supposed to use the rule
a^(m/n)= n
(the n-root) (don't know how to type it) and under the root symbol a^m
and the other rule is (a^x)(a^b)= a^(x+b)
The book calls this Radical Ecponents and Radical Expretions.
My problem is that it only says X, another problem I had, I can solve
(I will use ,- to symbolise the root)
to give you an idea on another problem how this is supposed to be solved
[y^ (-1/4)][y(3/4)] (multiply the two terms)
Following the rule
4,- [y^(-1)][y^3] (the for stands for the 4th root and the rest is under the root symbol)
using the rule of multiplication of the powers you then get
4,- y^2
which is the same as the following and keeping in mind that there has to be some number to the power of 4.
4,- (y^(1/2)^4)
The fours cancel and then you have y^ (1/2)
Note that (1/2)4 is the same thing as 2 so it's like factoring too.
I just can't do the problem I showed you. I hope I gave you enough info to help me out!!
Thanks you!
(Original question below)
Please read and then help me!
(x^(-3/5))
----------- divide
x ^ (1/5)
I know the problem then needs to look like this:
(x^(-3/5))(x^(-1/5))
(multiply the two above)
Then it needs to look like this:
(I can't write it though, so I'll tell you)
The 5th root out of (x^(-3)(x^(-1)
Then that adds up to the 5th root out of x^(-4)
and this is were I need help. To get rid of the fifth root there neeeds to be something to the power of 5 under the root symbol, but how do I get there? If my math to this point isn't correct, please correct it. I need Help!
I thought I had answered your question before.
Your original expression of
(x^(-3/5))
----------- divide
x ^ (1/5)
reduces or can be simplified to x^(-4/5)
Other than writing this in several different forms such as (x^-4)^(1/5) or (1/x^4)^(1/5)
there is no need or no method to "get rid of" the fifth power unless you have a value for x
If you had an equation containing that expression there would be ways to solve for x by manipulating the fifth power using power rules.
I am supposed to use the rule
a^(m/n)= n
(the n-root) (don't know how to type it) and under the root symbol a^m
and the other rule is (a^x)(a^b)= a^(x+b)
The book calls this Radical Ecponents and Radical Expretions.
My problem is that it only says X, another problem I had, I can solve
(I will use ,- to symbolise the root)
to give you an idea on another problem how this is supposed to be solved
[y^ (-1/4)][y(3/4)] (multiply the two terms)
Following the rule
4,- [y^(-1)][y^3] (the for stands for the 4th root and the rest is under the root symbol)
using the rule of multiplication of the powers you then get
4,- y^2
which is the same as the following and keeping in mind that there has to be some number to the power of 4.
4,- (y^(1/2)^4)
The fours cancel and then you have y^ (1/2)
Note that (1/2)4 is the same thing as 2 so it's like factoring too.
I just can't do the problem I showed you. I hope I gave you enough info to help me out!!
Thanks you!
(Original question below)
Please read and then help me!
(x^(-3/5))
----------- divide
x ^ (1/5)
I know the problem then needs to look like this:
(x^(-3/5))(x^(-1/5))
(multiply the two above)
Then it needs to look like this:
(I can't write it though, so I'll tell you)
The 5th root out of (x^(-3)(x^(-1)
Then that adds up to the 5th root out of x^(-4)
and this is were I need help. To get rid of the fifth root there neeeds to be something to the power of 5 under the root symbol, but how do I get there? If my math to this point isn't correct, please correct it. I need Help!
I thought I had answered your question before.
Your original expression of
(x^(-3/5))
----------- divide
x ^ (1/5)
reduces or can be simplified to x^(-4/5)
Other than writing this in several different forms such as (x^-4)^(1/5) or (1/x^4)^(1/5)
there is no need or no method to "get rid of" the fifth power unless you have a value for x
If you had an equation containing that expression there would be ways to solve for x by manipulating the fifth power using power rules.
Answers
There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.