The last line is wrong:
(5y-1)x= 4
5yx= 4+x
y= (x+4)/5x
I still need help with finding the inverese of one to functions.
Find the inverese of the one to one function.
16. f(x)= 4/(5x-1)
This is what I've done so far.
y=4/(5x-1)
x= 4/(5y-1)
(5y-1)x= 4(5y-1)
Then I am not too sure what to do next.
3 answers
y=(x+4)/5x, doesnt match up with what I am suppose to get.
I am suppose to get:
a. f^-1(x)=4/(5y) +1/5, b. f^-1(x)=4/(5x) +1/(5), c. f^-1(x)= -1/(5) -4/(5x), or d. f^-1(x)=5x-1/(4)
I am suppose to get:
a. f^-1(x)=4/(5y) +1/5, b. f^-1(x)=4/(5x) +1/(5), c. f^-1(x)= -1/(5) -4/(5x), or d. f^-1(x)=5x-1/(4)
y=(x+4)/5x= 1/5 +4/5x
x=1/5+4/5y
x=1/5+4/5y
1 answer