Question

I still don't know how to completely solve systems by substitution. Can someone please help me?

1. Y=-11+x
3x+10y=-6
How would you know where to plug in the right section of the equation in a certain place?

2. Y =6x-5
Y =-x+9

Answer 1

substitute the value of a variable from one equation into the other equation. For #1, we are told

y = x-11

So, substitute that into the other equation, and we have

3x + 10(x-11) = -6
3x + 10x - 110 = -6
13x = 104
x = 8
So, y = x-11 = 3
Be sure to check the solution to make sure it satisfies both original equations.

Now do #2 in just the same way.

Answer 2

Okay! On #2 how would you set it up since there's no equal signs