1)
Well, to make those nitrogen atoms come out, we will need the least common multiple of 2 and 3 which is 6, so try 5 nitrogen atoms on each side. That means 2 of NaN3 and 3 of N2, then work on the sodium
2 NaN3 --> ? Na + 3 N2
I guess we can all see that our question mark is really 2
2)
I have 1 Nitrogen on the left and one on the right
I have 4 Oxygens on the left and 4 on the right
That will do as is
3)
I have 1 Li left and 2 on the right so try 2 LiOh
2LiOH + CO2 -> Li2CO3 + H2O
I now have 2 H atoms left and 2 right -- ok
I now have 4 O atoms left and 4 right-- ok
I now have 1 C atom left and one right -- ok
so I am finished
I really need help for my homework on balancing equations please show all the work including the coeffients if needed.
I need help with 3 questions,
1) NaN3 -> Na + N2
2) NO2 + O2 -> NO + 03
3) LiOH + CO2 -> Li2CO3 + H2O
3 answers
1)
Well, to make those nitrogen atoms come out, we will need the least common multiple of 2 and 3 which is 6, so try 66 nitrogen atoms on each side.
Well, to make those nitrogen atoms come out, we will need the least common multiple of 2 and 3 which is 6, so try 66 nitrogen atoms on each side.
Or maybe just 6