I realized that I was typing the problems incorrectly. So here is the correct problem,
27^-2/3
____________
27 ^-1/3
3 answers
Thank you Maxine, I will get started on helping you with this right away.
You're welcome
27^-2/3
____________
27 ^-1/3
First with your given problem, you need to convert each negative exponent into a fraction. We will start with the denominator.
27 ^ -1/3 turns into: 1/(cube root of 27)
1/(cube root of 27) = 3
Your problem now currently looks like this:
27^-2/3
____________
1/3
Now let's do the same for the numerator.
27 ^ -2/3 turns into: 1 / 27 ^ (2/3)
27 ^ (2/3) = 3^2 = 9
Your problem now currently looks like this:
1/9
____________
1/3
We now have to divide the fractions, so we use the reciprocal of the denominator and then multiply.
Your problem is now
(1/9) x (3/1)
1/9 of 3 is 1/3.
Your final answer is 1/3.
____________
27 ^-1/3
First with your given problem, you need to convert each negative exponent into a fraction. We will start with the denominator.
27 ^ -1/3 turns into: 1/(cube root of 27)
1/(cube root of 27) = 3
Your problem now currently looks like this:
27^-2/3
____________
1/3
Now let's do the same for the numerator.
27 ^ -2/3 turns into: 1 / 27 ^ (2/3)
27 ^ (2/3) = 3^2 = 9
Your problem now currently looks like this:
1/9
____________
1/3
We now have to divide the fractions, so we use the reciprocal of the denominator and then multiply.
Your problem is now
(1/9) x (3/1)
1/9 of 3 is 1/3.
Your final answer is 1/3.