Well, it is easy if one considers energy.
if velocity doubles, then velocity quadruples
Vf^2=4Vi^2
but also we know from energy,
Vf^2=Vi^2+2*g*h where h is the distance fell.
so
4Vi^2=Vi^2+2gh
h= 3Vi^2/2g
Now how much time passes for it to go h?
average velocity= (Vf+Vi)/2= 3Vi/2
time= h/avg velocity= you do it. You know Vi
i posted this question before however i did not understand drwls explanation. anybody else want to try ?
Sam tosses a ball horizontally off a footbridge at 3.1 m/s. How much time passes after he releases it until its speed doubles?
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does stand for gravity?
g is the acceleration due to gravity, 9.8m/s^2
hmm i somehow got .3161 but that's wrong according to my online instructor.hmm
4 answers