I posted this before and didn't get an answer but I'm still stuck...

A 3m long, 290N uniform rod is held in a horizontal position by two ropes at its ends. The left rope makes an angle of 150 degrees with the rod, and the right rope makes an angle theta with the horizontal. An 86 N howler monkey hangs motionless 0.5 m from the right end of the rod as he carefully studies you. Calculate the tensions in the two ropes and the angle theta.

1 answer

moments are around right end
first up = down
Tl sin 30 + Tr sin theta = 290 + 86
then right = left
Tl cos 30 = Tr cos theta
now moments
(Tl sin 30) (3) = 290 (1.5) + 86 (0.5)
well 1.5 Tl = 435 + 43 = 478
so Tl = 319 N
so go back and put that in
Tl sin 30 + Tr sin theta = 290 + 86
319/2 + Tr sin theta = 376
Tr sin theta = 217
and
Tl cos 30 = Tr cos theta
319(.866) = Tr cos theta
Tr cos theta = 276
so
tan theta = 217 / 276
onward ....