The balls initial momentum and gravity determine how long it is in the air. But the force of gravity is proportional to mass...Weight=mg
intialmomenum-mg*deltaTime=0
deltatime in the air= initialmomentum/mg
= mVi/mg= Vi/g
So because the force of gravity is proportional to gravity, as is momentum, mass is not revelent to the time in air. The time it is in the air determines its height as it goes up to its stopping point.
I posted something concerning this question earlier.. and thank you for checking and letting me know of my mistake.
I said that for a given velocity, the height does not depend on the mass of the ball. How could I explain this, besides the fact that when calculuting it, I don't need the mass?
Thanks again.
2 answers
THanks for the explanation.