since there is a common ratio between terms,
(x+4)/(4x+1) = (10-x)/(x+4)
Now just solve for x.
I NEED URGENT HELP WITH THIS QUESTION!!!!
Question:
The terms of a geometric sequence are 4x+1, x+4, and 10-x. Determine the value of x.
4 answers
Use your definition.
(x+4)/(4x+1) = (10-x)/(x+4)
(x+4)^2 = (4x+1)(10-x)
x^2 + 8x + 16 = 40x - 4x^2 + 10 - x
5x^2 - 31x + 6 = 0
solve for x, it factors
(x+4)/(4x+1) = (10-x)/(x+4)
(x+4)^2 = (4x+1)(10-x)
x^2 + 8x + 16 = 40x - 4x^2 + 10 - x
5x^2 - 31x + 6 = 0
solve for x, it factors
Did that and it didn’t work. I am not getting the correct value for x. x = 6.
It would be great if someone showed me the steps on how to solve the question
It would be great if someone showed me the steps on how to solve the question
I told you it factored
5x^2 - 31x + 6 = 0
(x-6)(5x-1) = 0
x = 6 or x = 1/5
if x = 6, your terms are: 25, 10, and 4
notice 10/25 = 4/10 = 2/5
if x = 1/5, your terms are : 9/5, 21/5, and 49/5
is (21/5) ÷ (9/5) = (49/5) ÷ (21/5) ??
5x^2 - 31x + 6 = 0
(x-6)(5x-1) = 0
x = 6 or x = 1/5
if x = 6, your terms are: 25, 10, and 4
notice 10/25 = 4/10 = 2/5
if x = 1/5, your terms are : 9/5, 21/5, and 49/5
is (21/5) ÷ (9/5) = (49/5) ÷ (21/5) ??