each bulb is a separate branch of the circuit, and so has the same voltage drop.
Since they have the same resistance, each bulb gets a current of 1.5V/6.3Ω = 0.238A
Note that 1/Rt = 0.317, so Rt = 3.15 = 6.3/2 Ω
I need to understand how to calculate the final 2 steps of this problem. Appreciate any help:
For a circuit, consisting of a single battery and two light bulbs in parallel, what is the total resistance of the circuit if each light bulb has a resistance of 6.3 ohms?
1/Rt=1/R1+1/R2 = .317 ohms
How much current is being drawn from the battery if the battery provides 1.5 Volts?
DON'T UNDERSTAND
What is the current through each bulb? DON'T UNDERSTAND
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1 answer