(64n^9)^2/3
When you have an exponent of an exponent, you multiply the two. (9 * 2/3 = 6)
64^2/3 (n^6)
Cube root of 64 = 4 (4*4=16, 16*4 = 64)
4^2 = 16
(64n^9)^2/3 = 16n^6
I need to simplify the following rational exponent:
(64n^9)^2/3
I've done the following but don't think this is right:
= 3|64n^18
= 4n^2.62
I don't know how to type in the root symbol so I used | to mean root. Can someone please verify this and if incorrect please explain where I went wrong? Thank you very much...
1 answer
1 answer