there are 10^4 4-digit integers
there are P(10,4) with no repeats
divide P(10,4)/10^4 for the probability of no repeats.
You want 1 minus that probability.
1 - P(10,4)/10^4 = 62/125
so, almost 50%
I need to show work for this but I don't know how.
Erik wants to form 4-digit integers using only the digits 1, 2, 3, and 4. He is allowed to
repeat digits. What is the probability that he forms a 4-digit integer where at least one digit
repeats? Express your answer as a common fraction.
1 answer