i need to rearrange the following equations, to make x the subject .

Question

r = sx^2
2t

and

6y = 9 – 3x

can some 1 help me im realy stuck. i need to work it out step by step.

the 2t is meant 2 be under sx^2 meaning dived by

r= sx^2/2t

multipy both sides by 2t

r2t= sx^2
divide both sides by s

2rt/s= x^2

take the square root of each side

sqrt(2rt/s) = x
x=sqrt(2rt/s)

On the second, I will gladly critique your work. Start with adding 3x to both sides.