i need to rearrange the following equations, to make x the subject .
r = sx^2
2t
and
6y = 9 – 3x
can some 1 help me im realy stuck. i need to work it out step by step.
the 2t is meant 2 be under sx^2 meaning dived by
r= sx^2/2t
multipy both sides by 2t
r2t= sx^2
divide both sides by s
2rt/s= x^2
take the square root of each side
sqrt(2rt/s) = x
x=sqrt(2rt/s)
On the second, I will gladly critique your work. Start with adding 3x to both sides.