To prepare a stoichiometrically balanced solution with a molar ratio of 3.1:1:1 for urea, sulfuric acid, and water, you will need to follow these steps:
1. Determine the molar masses of each compound:
- Urea (NH2CONH2): 60.06 g/mol
- Sulfuric acid (H2SO4): 98.08 g/mol
- Water (H2O): 18.015 g/mol
2. Calculate the total moles of each compound required based on the given molar ratio:
- For urea: 3.1 moles
- For sulfuric acid: 1 mole
- For water: 1 mole
3. Calculate the mass of each compound required using the molar masses:
- Mass of urea = moles of urea x molar mass of urea = 3.1 moles x 60.06 g/mol = 186.426 g
- Mass of sulfuric acid = moles of sulfuric acid x molar mass of sulfuric acid = 1 mole x 98.08 g/mol = 98.08 g
- Mass of water = moles of water x molar mass of water = 1 mole x 18.015 g/mol = 18.015 g
Therefore, to prepare a stoichiometrically balanced solution of urea, sulfuric acid, and water in a molar ratio of 3.1:1:1, you will need 186.426 g of urea, 98.08 g of sulfuric acid, and 18.015 g of water.
I need to prepare a stchiometically balanced solution of urea , Shulpuric acid and water in a molar ratio of 3.1:1:1 , how much material should I use ?
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