I assume you mean x-intercepts.
Since e^0 = 1, you just need to solve
x^2-9x+20 = 0
Back to Algebra I, now ...
I need to find the intercepts for:
f(x)=e^(x^2-9x+20)-1
2 answers
for the y-intercept, let x = 0
f(0) = e^(0-0+20) - 1
= e^20 - 1
that is really big, appr 485,165,194
for the x-intercept, let y = 0
e^(x^2-9x+20)-1 = 0
e^(x^2-9x+20) = 1
e^(x^2-9x+20) = e^0
so x^2 - 9x + 20 = 0
(x-5)(x-4) = 0
x = 5 or x = 4
f(0) = e^(0-0+20) - 1
= e^20 - 1
that is really big, appr 485,165,194
for the x-intercept, let y = 0
e^(x^2-9x+20)-1 = 0
e^(x^2-9x+20) = 1
e^(x^2-9x+20) = e^0
so x^2 - 9x + 20 = 0
(x-5)(x-4) = 0
x = 5 or x = 4
1 answer