your title says, "geometric series"
none of them are a geometric series
1) I think you have a typo and meant
5/1 + 8/1 + 11/1 + 14/1 + . .
first of all the 1's in the denominator are redundant and you are simply looking at
5 + 8 + 11 + 14 + ... which is (3n+2) with n starting at 1
2) the numerator is generated by n^2 + 5
and the denominator by 3n+2
do you get the idea?
I need to find the equations of the following, using Ó (and the n=1 which is at the bottom of the Ó) (and infinity is at the top of the Ó)
1) 5/1 + 8/1 + 1/1 + 14/1 + . . .
2) 6/5 + 9/8 + 14/11 + 21/14 + . . .
3) -6/3 - 4/4 - 2/5 - 0 + . . .
4) 9/1 + 36/4 +27/9 + 144/16 + . . .
5) 20/4 + 25/5 + 30/6 + 35/7 +40/8 + ...
2 answers
i still need assistance with the rest i don't understand how yu get hose answers..
1 answer