I need to find the dy/dx of x^2ln(x^2)I tried to do it the way I thought, but it did not come out right.

Answer 1

dy/dx= 2xlnx^2 + x^2/x^2 *2x
reduce it.

Answer 2

If I did it correctly I got 4x ln (x^2).

Answer 3

I got 2x (1+lnx^2)

Answer 4

You are right