since ABCD is a rhombus, all the sides are equal.
So, we already know that AD=AB=BC=CD
Since BD is an angle bisector,
<ABD = <DBC
So, we have SAS and the triangles are congruent.
I need to figure out this proof, the figure is two triangles forming a rhombus.
Given: segment BD is the angle bisector of triangle ABC and triangle ADC
Prove: Triangle ABD is congruent to Triangle CBD
So far I have segment BD is the angle bisector of triangle ABC and triangle ADC (Given), and segment BD is congruent to segment BD (Reflexive property)... where do I go on from here?
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