I need to fid the activation energy but i forgot how to solve for Ea

Question

4.58*10^-15=e^(Ea/2537.02)

can you show the work thank you

Answer 1

take the ln of both sides:
ln [4.58*10^-15] = ln [e^(Ea/2537.02)]
*since ln has a base of e, the term at the right side becomes:
ln [4.58*10^-15] = (Ea/2537.02)

now you solve for Ea. :)

Answer 2

thanks that helps alot