You're absolutely right.
12.5 g ethylene glycol in 100 g H2O is 12.5 g solute in (12.5g + 100 g) = 112.5 solution. Then use density to convert grams solution to L soln.
I need to calcuted the molarity from this
12.5 g of ethylene glycol antifreeze dissolved in o.100kg of water. Density of solution is 1.0 g/mL
I know molarity if mole of solute / L of solution.
I am confused on how to find the L of solution. Do I add 12.5 and .100g to get the solution mass. Since 12.5 is solute and .100 g is solvent.
Please help!!!!!
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