ANYTHING^0 = 1
no more steps needed
I need to be shown the steps on how you derive at this answer
(5a^7 / 2b^5c)^0 = 1
2 answers
here, for any old x
x^0 * x^1 = x^(1+0) = x^1
so
x^0 was 1
x^0 * x^1 = x^(1+0) = x^1
so
x^0 was 1