i need the antiderivative of sinxcosx dx for intergral pie/2 to 0 thanks.

sin(x)cos(x)dx = sin(x)d[sin(x)] =

1/2d[sin^2(x)]

Similar Questions

8sin^2x+sinxcosx+cos^2x=4
1. 2 answers
Suppose f(x) is a continuous function. Then a function F(x) such that F'(x) = f(x) is called:A.) the indefinite integral of f
1. 1 answer
How do I prove that7sin^2x - sinxcosx = 6 can also be written as tan^2x + tanx - 6 = 0 ?
1. 2 answers
Which of the following are antiderivatives of f(x)=sinxcosx?I f(x)=(sin^2* x)/2 II f(x)=(cos^2* x)/2 III f(x)=-cos(2x)/4
1. 2 answers