recall that y' is the slope of the tangent line. The slope is the tanθ, so
y'(x) = 4x^3-3x^2+7
y'(2) = 4*8-3*4+7 = 27 = tanθ
θ = 87.9°
The line x-2y-1=0 has slope 1/2
So, where is y' 1/2?
y' = 2x-3
2x-3 = 1/2 when x = 7/4
I need some help with my maths questions please!
What angle does the tangent to the curve y=x^4-x^3+7x make with the positive direction of the x-axis at the point where x=2?
Find any x values for which the gradient of the tangent to the curve y=x^2-3x-1 is parallel to the line x-2y-1=0.
1 answer
1 answer