starting with the 4th term, we have a definite pattern and the general term from that point is
1/(3^n + √(n+1) ) , where n starts with 1
Since you wanted to "write the series", why don't we just add the first 3 terms and begin the serious stuff with term 4
4 + 1/5 + 3/10 = 9/2
so the sum
= 9/2 + sigma( 1/(3^n + √(n+1) ) from n = 1 to infinity
I need help writing the series 4 + 1/5 + .3 + 1/(3 + sqrt 2) + 1/(9+ sqrt 3) + 1/(27 + sqrt 4) + 1/(81 + sqrt 5 ....
I have played with using irrational numbers, natural log and a vast variety of exponential arrangements. Any help to get me going in the right direction would be very appreciated.
1 answer
1 answer