I need help with these kind of problems. We are dealing with word problems and/or pictures that are solved by the Law of Sin or Cosine. If any one kows a wonderful web site that can help with these, I would greatly appreciate it.

A parollelogram has side lengths 3 and 5, and one angle is 50 degrees. Find the lengths of the diagonals.

5 answers

Shorter diagonal: the angle between sides 3 and 5 is 50º (SD for short diagonal)

SD^2 = 5^2 + 3^2 - 2(5)(3)cos 50º

take it from there.

Let me know what you get for the equation of the longer diagonal.
I got 3.8, we round to the nearest tenths.
3.8 was my answer for the short diagonal.
I'm not sure how to find the long diagonal.
for the longer, same sides except the angle between them is now 130º

LD^2 = 5^2 + 3^2 - 2(3)(5)cos130
= 25 + 9 - 30(-.642788)
= 7.2996
= 7.3

Notice this time the last term was actually added because of the double negatives.
last two lines should have been

LD = 7.2996
= 7.3

(I still had it equal to LD^2)