I need help with the unit 8 lesson 2 connexus math exam can someone help me pls
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Of course! I'd be happy to help you with the Unit 8 Lesson 2 exam. Please let me know what specific questions you are struggling with or need assistance with, and I'll do my best to guide you through them.
What is a simpler form of the radical expression?%C2%A0 1296x16y12−−−−−−−−−√
To simplify the given radical expression √(1296x^16y^12), you will want to factor out perfect squares from the radicand (the number inside the square root).
First, you can simplify the expression by breaking down 1296, 16, x^16, and y^12 into their prime factors:
1296 = 2^4 * 3^4
16 = 2^4
x^16 = (x^8)^2
y^12 = (y^6)^2
Therefore, the expression can be rewritten as:
√(2^4 * 3^4 * (x^8)^2 * (y^6)^2)
By using the property of radicals that √(ab) = √(a) * √(b), you can simplify the expression further:
2^2 * 3^2 * x^8 * y^6
This simplifies to:
= 36x^8y^6
So, the simpler form of the given radical expression is 36x^8y^6.
First, you can simplify the expression by breaking down 1296, 16, x^16, and y^12 into their prime factors:
1296 = 2^4 * 3^4
16 = 2^4
x^16 = (x^8)^2
y^12 = (y^6)^2
Therefore, the expression can be rewritten as:
√(2^4 * 3^4 * (x^8)^2 * (y^6)^2)
By using the property of radicals that √(ab) = √(a) * √(b), you can simplify the expression further:
2^2 * 3^2 * x^8 * y^6
This simplifies to:
= 36x^8y^6
So, the simpler form of the given radical expression is 36x^8y^6.
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