Asked by Junior
I need help solving this equation.
[SQRT(x + 3)] - [SQRT(x - 2)] =1
I know I am supposed to square each side however my teacher tells me I ahve to foil the lefthand side of the equation. Cna someone please help me with this.
Thank you.
[SQRT(x + 3)] - [SQRT(x - 2)] =1
I know I am supposed to square each side however my teacher tells me I ahve to foil the lefthand side of the equation. Cna someone please help me with this.
Thank you.
Answers
Answered by
bobpursley
well, if you square both sides
you get (FOIL)
x+3-2sqrt(x-2)sqrt(x+3) + x-2=1
2x+2- 2sqrt( x^2+x-6)=1
or 2x+2-2=2sqrt(x^2+x-6)
square both sides
4x^2=4(x^2+x-6)
x=6
you get (FOIL)
x+3-2sqrt(x-2)sqrt(x+3) + x-2=1
2x+2- 2sqrt( x^2+x-6)=1
or 2x+2-2=2sqrt(x^2+x-6)
square both sides
4x^2=4(x^2+x-6)
x=6
Answered by
Junior
Thank you.
Answered by
Junior
Would I do the same thing with this equation?
[SQRT(x + 7)] - 2[SQRT(x)] =-2
Beacause I see what you have showed me BUt i am stll a little bit confused. Please if you have the time help me. Thank you.
[SQRT(x + 7)] - 2[SQRT(x)] =-2
Beacause I see what you have showed me BUt i am stll a little bit confused. Please if you have the time help me. Thank you.
Answered by
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