I need help please.

"what voluma [in mL] at STp will be occupied by 0.0035 mol of methane [CH4]"

THANK YOU SOO MUCH!

2 answers

WEll, one mole is 22400 ml.

So do it in proportion:

.0035/1 =V/22400ml
is that for every mole in problems like these?

because i thought it was 6.022x10^23