note that
x^2-1 = (x-1)(x+1)
x^3-1 = (x-1)(x^2+x+1)
x^4-1 = (x-1)(x^3+x^2+x+1)
so, 3^251-1 = (3-1)(3^250+3^249+...+3^1+1)
So your sum is just (3^251-1)/(3-1)
I need help on this question. My aunt doesn't understand it so can you help me?
1+3+3^2+3^3+3^4+••••••+3^250=?
The "^" is for Square, cube and ect.
It also includes X= 3^?-1
Can you help me please?
1 answer